- Probability that at least at least one black ball is picked in the first two pickings = $1- (75/100 \times 75/100) = 0.44 $
- Probability that at least one black ball with a red dot is picked in the first two pickings = $ 1- (95/100 \times 95/100) = 0.09 $
The probability that no black ball with a red dot is picked given that at least one black ball is picked is $(1 -2)/1 = 0.35/ 0.44 = 0.79 $