1 1 vote RST 7.5 interrupt in 8085 microprocessor executes the interrupt service routing from interrupt vector location 0000H 0075H 003CH 0034H CO & Architecture gate1997 co-and-architecture 8085-microprocessor out-of-gatecse-syllabus + – Kathleen 3.8k views answer comment Share Follow Print See 1 comment 1 1 comment reply P0535_Yedidyah_Sagar commented Oct 11, 2025 reply Follow flag Out of cse syllabus 0 0 replyShare Please log in or register to add a comment.
6 6 votes RST 7.5 Location will be 7.5*8 = 60. // 8085 is 8 bit processor 60 in hexadecimal will be 003C H Digvijay Pandey answered Jun 9, 2015 Digvijay Pandey comment Share Follow See 1 comment 1 1 comment reply mohit jangid 1 commented Dec 25, 2015 i edited by mohit jangid 1 Dec 26, 2015 reply Follow flag Why multiply with 8 bit? We should multiply by IVT Entry size in bytes. Isn't it? 0 0 replyShare Please log in or register to add a comment.
