0 0 votes CO & Architecture + – abhishekmehta4u 341 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 1 1 vote 1500 rotation --------> 1 sec 1 rotation ----------> $\frac{1}{1500}$ sec Avg rotation time = $\frac{1}{1500 × 2}$ sec = 0.33 ms Now 1 track data in 1 rotation i.e 1000 byte -------> $\frac{1}{1500}$ sec 1500 byte --------> $\frac{1 × 1500}{1000 × 1500}$ = 1 ms Seek time given = 15 ms Total access time = Avg Seek time + Avg Rotation time + Data transfer time = 15 ms + 0.33 ms + 1 ms = 16.33 ms amit1 answered Jul 11, 2018 • selected Jul 11, 2018 by abhishekmehta4u amit1 comment Share Follow 0 reply Please log in or register to add a comment.