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The difference between the number of states in minimal DFA and minimal NFA, which accepts all strings end with 3rd bit as b is ________. [Assume Σ = {ab,}]

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from right, nth bit fixed , the Minimal DFA has 2n states and Minimal NFA has n+1 states

therefore substitute the value of n , therefore DFA have 8 states and NFA have 4 states

therefore required answer = 8 - 4 = 4

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