#self doubt

Question

 

How to solve it ?

Comments

Oo I  done it wrong :3

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yes , Shaik Masthan  you're  right

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i posted my answer, if you want, you may check.

Answer 1

there is only one flipflop, so state diagram have state₀ and state₁.

state₀ means Q=0 and state₁ means Q=1

you have only one input that is A.

 

what happens if A=1 on state₀ ?

X₁=0 and X₀=1 due to state₀ ==> Y = A.X₁ + A' . X₀ = 1.0 + 0.1 = 0 ==> S = 0 ==> R=1

if S=0 and R=1 then Q=0

∴ if A=1 on state₀ = state₀

 

what happens if A=0 on state₀ ?

X₁=0 and X₀=1 due to state₀ ==> Y = A.X₁ + A' . X₀ = 0.0 + 1.1 = 1 ==> S = 1 ==> R=0

if S=1 and R=0 then Q=1

∴ if A=0 on state₀ = state₁

 

what happens if A=1 on state₁ ?

X₁=1 and X₀=0 due to state₁ ==> Y = A.X₁ + A' . X₀ = 1.1 + 0.0 = 1 ==> S = 1 ==> R=0

if S=1 and R=0 then Q=1

∴ if A=1 on state₁ = state₁

 

what happens if A=0 on state₁ ?

X₁=1 and X₀=0 due to state₁ ==> Y = A.X₁ + A' . X₀ = 0.1 + 1.0 = 0 ==> S = 0 ==> R=1

if S=0 and R=1 then Q=0

∴ if A=0 on state₁ = state₀

Graphical representation is

Comments

@Shubham Aggarwal

If you really get the concept from my answer, or it is really helped to you then choose it as BEST.

Otherwise no meaning of choosing it as BEST.

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Shubham Aggarwal 

hey my real name is sumit ...  I am male .xD :p

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It's okay bro  nevermind  :p