The PDF of a uniform distribution between 7 PM and 9 PM is:
f(t) = 1/2, for 7 <= t <= 9 & 0, otherwise
We want to find the probability of the call arriving between 8:30 PM and 8:40 PM, given that it hasn't arrived yet. This is a conditional probability.
Conditional Probability:
P(A|B) = P(A and B) / P(B)
In our case:
- A: The call arrives between 8:30 PM and 8:40 PM.
- B: The call hasn't arrived by 8:30 PM.
Calculating P(A and B):
This is the probability that the call arrives between 8:30 PM and 8:40 PM. We can calculate this by integrating the PDF over this interval:
P(A and B) = ∫[8.5, 8.667] (1/2) dt = (1/2) * (8.667 - 8.5) = 0.0833
Calculating P(B):
This is the probability that the call hasn't arrived by 8:30 PM. Since the call is equally likely to arrive at any time between 7 PM and 9 PM, and we know it hasn't arrived by 8:30 PM, the probability that it hasn't arrived is the ratio of the remaining time interval (30 minutes) to the total time interval (120 minutes):
P(B) = 30/120 = 0.25
Calculating the Conditional Probability:
P(A|B) = P(A and B) / P(B) = 0.0833 / 0.25 = 0.3333
Therefore, the probability that the call arrives in the next 10 minutes, given that it hasn't arrived yet, is approximately 0.3333 or 33.33%.