Register

Subnetting
closed

• closed by
1,151 views
3 votes
3 votes
closed as a duplicate of: psu
With an IP address of 100, you currently have 80 subnets. What subnet mask should you use to maximize the number of available hosts?

A. 222

B. 233

C. 241

D.252
• closed by
User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

0 votes
0 votes
1 answer
1
iarnav asked Oct 30, 2018
456 views
#CN Subnetting Self Doubt.
Given Subnet mask is 255.255.31.0 then how can one conclude that The subnet mask 255.255.x.x belongs to class B type(IP address range will be from 128.1.0.1 to 191.255.255.254) I get that from 255.255 N/w id = 16 bits but then how can we write range of ip addresses? @Shaik Brother can you see this?
Given Subnet mask is 255.255.31.0 then how can one conclude that The subnet mask 255.255.x.x belongs to class B type(IP address range will be from 128.1.0.1 to 191.255.2...
User Avatar
1 votes
1 votes
1 answer
2
vupadhayayx86 asked Oct 16, 2018
1,103 views
Subnetting
You need to configure a server that is on the subnet 192.168.19.24/29. The router has the first available host address. Which of the following should you assign to the server? A. 192.168.19.0 B. 192.168.19.33 C. 192.168.19.26 D. 192.168.19.31
You need to configure a server that is on the subnet 192.168.19.24/29. The router has the first available host address. Which of the following should you assign to the se...
User Avatar
4 votes
4 votes
2 answers
3
shashank023 asked Aug 27, 2017
2,212 views
Subnetting
Let host X has IP address 11.110.2.112 and host Y has IP address 11.110.2.92 and both hosts use the same netmask Z. which of the network masks Z given below can used if both hosts are in the same network? 255.255.255.224 255.255.255.252 255.255.255.193 255.255.128.0
Let host X has IP address 11.110.2.112 and host Y has IP address 11.110.2.92 and both hosts use the same netmask Z. which of the network masks Z given below can used if b...
User Avatar
Link Copied!