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HOW??

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See total required bits in opcode for 2 address feild is 6 so we can have 2^6 instruction in which some or allof them have been in 2 address instruction which we don't know .Take it as x

now total no. of 1 address insttruction will be (2^6-x)*2^7

as given 1 address instruction is 1024 we equate the above one with this value

(2^6-n)*2^7=1024

solving this will give you 56 which is the correct answer

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VJ2793 asked Nov 19, 2018
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In the solution to this question, it is given that the number of rotations needed is 2.75. How we got 2.75?