0 votes 0 votes if there is no allocation sequence that allows the processes to finish executing, then the system is in an unsafe state. This is not equivalent to the "If the system is in an unsafe state, then there is no allocation sequence that allows the processes to finish executing Operating System deadlock-prevention-avoidance-detection + – Gurdeep Saini asked Nov 3, 2018 • edited Dec 15, 2018 by Gurdeep Saini Gurdeep Saini 2.2k views answer comment Share Follow See all 12 Comments See all 12 12 Comments reply Show 9 previous comments kumar.dilip commented Nov 5, 2018 reply Follow Share If the system is in safe state It is guaranteed that There will not be Deadlock or There might be at least any sequence that may cause Deadlock ???? 1 votes 1 votes Gurdeep Saini commented Nov 5, 2018 reply Follow Share @dilip If the process is in a safe state, it will never lead to deadlock. If the process is in an unsafe state, it may or may not lead to deadlock. 1 votes 1 votes kumar.dilip commented Nov 5, 2018 reply Follow Share I know. I am asking There might be any sequence or not For which There will be deadlock in safe state ?? 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes If the process is in a safe state, it will never lead to deadlock. If the process is in an unsafe state, it may or may not lead to deadlock. Kunal Kadian answered Nov 3, 2018 Kunal Kadian comment Share Follow See 1 comment See all 1 1 comment reply Gurdeep Saini commented Nov 3, 2018 reply Follow Share cam anybody give the example that when a process in unsafe state and have no deadlock .i tried to find the example but not found all of tham given only theory 0 votes 0 votes Please log in or register to add a comment.
