The given grammar is LL(3).
Some prorperties of LL grammar are that it should not be ambiguous, non determinstic and left recursive.
So if we see for LL(1): it has a look ahead of 1 so that makes this grammar non deterministic as after seeing a we dont whether it is S->a or S->ab or S->abc.. So not LL(1)
LL(2): after seeing ab we dont know S->ab or S->abc.
LL(3) has a lookahead of 3 and this problem doesnot reside here. So the given grammar is LL(3).