MadeEasy WorkBook: Digital Logic - Multiplexer

Question

Can anyone explain this.?? 

then.
\[
f=\frac{1}{T}=\frac{1}{2 \times 10^{-6}}=0.5 \times 10^{6}=0.5 \mathrm{MHz}
\]

Example-4.18 The logic function $F=A C+A B D+A C D$ is to be galized using an 8 to 1 multiplexer shown in the Figure, using $A, C$ and $D$ as ontrol inputs.
(i) Indicate the inputs to the applied at the terminals 0 to 7 .
(ii) Can the function be realize using a 4 to 1 multiplexer?

Solution:
(i)
\[
\begin{array}{l}
F=A C+A B D+A C D \\
=A C B+A C \bar{B}+A B D C+A B D \bar{C}+A C D \bar{B} \\
=A B C \bar{D}+A \bar{B} C \bar{D}+A \bar{B} C D+A B C D+A B \bar{C} D \\
=A C \bar{D}(\bar{B}+B)+A C D(B+\bar{B})+A \bar{C} D B \\
=\underbrace{\bar{D} C A}_{30}(B+\bar{B})+\underbrace{D C A}_{7^{n} \text { line }}(B+\bar{B})+\underbrace{D \bar{C} A}_{5^{\text {line line }}} B \\
=\bar{D} C A(1)+D C A(1)+D \bar{C} A \cdot(B)
\end{array}
\]
(ii) It can not be realized with a 4 to 1 multiplexer as
$5^{\text {th }}$ and $7^{\text {th }}$ lines are being used.
4.3.4 Decoders
- A dedoder have many inputs and many outputs.
- It is a combinational logic circuit that converts binary information from ' $n$ ' bit input lines to maximum ' $2^{\text {f }}$ unique output lines such that only one output line is activated for each one

Comments

can you please upload clear image of question??

---

Check now