TestBook(FLT)

Question

Compute effective access time in seconds for demand-paged memory. The memory access time is 180 ns and the average latency, seek time,transfer time is of 3ms,4ms,1ms repectively.Assume the probabilty of page fault is 0.4

Comments

Which equation is right

EMAT = (1-p) (Memory access time) + p * (Memory access time + average latency + seek time + transfer time )

OR

EMAT = (1-p) (Memory access time) + p * (average latency + seek time + transfer time )

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In case of page fault too the memory will be accessed , 

So I think 

EMAT = (1-p) (Memory access time) + p * (Memory access time + average latency + seek time + transfer time )

This shall be correct. 🤔