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L is regular <=> there exists a linear grammar for L.

Which way is it true and which way is it false?

Please explain in detail
in Theory of Computation by (195 points) | 47 views
The biconditional is true. (which means it correct both ways)

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and more over if

Let     L is:   A-> a   (RG)  and also Linear G

and S-> aSb | epsilon (which is linear. But for it we can't drive any RG)



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