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There are two candidates $P$ and $Q$ in an election. During the campaign, $40\%$ of the voters promised to vote for $P,$ and rest for $Q.$ However, on the day of election $15\%$ of the voters went back on their promise to vote for $P$ and instead voted for $Q.$  $25\%$ of the voters went back on their promise to vote for $Q$ and instead voted for $P.$ Suppose$,P$ lost by $2$ votes$,$  then what was the total number of voters?

  1. $100$
  2. $110$
  3. $90$
  4. $95$

8 Answers

1 1 vote

Let the number of voters be 100.

Then, the number of candidates which promised to vote for P = 40

and the no. of candidates promised to vote for Q = 100 – 40 = 60

According to question,

15% of 40 = 6 voters went back on their promise to vote for
P and instead voted for Q.

and 25% of 60 = 15 voters went back on their promise to vote
for Q and instead voted for P.

Number of Votes for P = 40 – 6 + 15 = 49

and Number of Votes for Q = 60 + 6 – 15 = 51

Difference of Votes = 51 – 49 = 2.

Also P lost by 2 Votes.

Number of Voters were 100.

reference: https://www.allinterview.com/showanswers/160596/two-candidates-p-q-election-during-campaign-40-voters-promised-vote-rest-however.html

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