17 17 votes There are two candidates $P$ and $Q$ in an election. During the campaign, $40\%$ of the voters promised to vote for $P,$ and rest for $Q.$ However, on the day of election $15\%$ of the voters went back on their promise to vote for $P$ and instead voted for $Q.$ $25\%$ of the voters went back on their promise to vote for $Q$ and instead voted for $P.$ Suppose$,P$ lost by $2$ votes$,$ then what was the total number of voters? $100$ $110$ $90$ $95$ Quantitative Aptitude general-aptitude quantitative-aptitude gate2011-ag percentage + – admin 12.8k views answer comment Share Follow Print See 1 comment 1 1 comment reply Ram Swaroop commented May 10, 2020 reply Follow flag Wording of language is really important so read carefully use of instead. 2 2 replyShare Please log in or register to add a comment.
1 1 vote Ans -> A) 100 Akash Kanase answered Dec 17, 2015 Akash Kanase comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote Let the number of voters be 100. Then, the number of candidates which promised to vote for P = 40 and the no. of candidates promised to vote for Q = 100 – 40 = 60 According to question, 15% of 40 = 6 voters went back on their promise to vote for P and instead voted for Q. and 25% of 60 = 15 voters went back on their promise to vote for Q and instead voted for P. Number of Votes for P = 40 – 6 + 15 = 49 and Number of Votes for Q = 60 + 6 – 15 = 51 Difference of Votes = 51 – 49 = 2. Also P lost by 2 Votes. Number of Voters were 100. reference: https://www.allinterview.com/showanswers/160596/two-candidates-p-q-election-during-campaign-40-voters-promised-vote-rest-however.html sutanay3 answered Jul 22, 2018 sutanay3 comment Share Follow 0 reply Please log in or register to add a comment.