0 votes 0 votes $\underset{x\rightarrow 0}{\lim}\sin\left(\dfrac{1}{x}\right)$ equals $-1$ $0$ $1$ Does not exist Calculus isi2016-dcg calculus limits + – gatecse asked Sep 18, 2019 • recategorized Nov 19, 2019 by Lakshman Bhaiya gatecse 255 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply `JEET commented Sep 26, 2019 reply Follow Share limit does not exist. 1 votes 1 votes Lakshmi Narayana404 commented Feb 5 reply Follow Share DNE, as x approaches to zero it just oscillates from -1 to 1. 2 votes 2 votes Please log in or register to add a comment.