recategorized by
505 views
1 votes
1 votes

Suppose $A$ and $B$ are orthogonal $n \times n$ matrices. Which of the following is also an orthogonal matrix? Assume that $O$ is the null matrix of order $n \times n$ and $I$ is the identity matrix of order $n$.

  1. $AB-BA$
  2. $\begin{pmatrix} A & O \\ O & B \end{pmatrix}$
  3. $\begin{pmatrix} A & I \\ I & B \end{pmatrix}$
  4. $A^2 – B^2$
recategorized by

1 Answer

1 votes
1 votes
The product of $2$ orthogonal matrices is an orthogonal matrix and the determinant of an orthogonal matrix $= +1$ or $-1$

 ${\begin{vmatrix} A &O \\ O & B \end{vmatrix}} = |AB|=1$

So this means ${\begin{pmatrix} A &O \\ O & B \end{pmatrix}} $ is also an orthogonal matrix.

Hence $B.$ is correct answer.

Related questions

0 votes
0 votes
0 answers
2
gatecse asked Sep 18, 2019
318 views
The set of vectors constituting an orthogonal basis in $\mathbb{R}^{3}$ is$\begin{Bmatrix} \begin{pmatrix} 1\\ -1 \\0 \end{pmatrix}&,\begin{pmatrix} 1\\ 1 \\0 \end{pmatri...
0 votes
0 votes
1 answer
3
gatecse asked Sep 18, 2019
492 views
If $$f(x) = \begin{bmatrix} \cos x & -\sin x & 0 \\ \sin x & \cos x & 0 \\ 0 & 0 & 1 \end{bmatrix}$$ then the value of $\big(f(x)\big)^2$ is$f(x)$$f(2x)$$2f(x)$None of th...
2 votes
2 votes
1 answer
4
gatecse asked Sep 18, 2019
442 views
Let $A$ be an $n \times n$ matrix such that $\mid A^{2} \mid\: =1$. Here $\mid A \mid $ stands for determinant of matrix $A$. Then$\mid A \mid =1$$\mid A \mid =0 \text{ o...