7 7 votes Consider two independent random variables $X$ and $Y$ having probability density functions uniform in the interval $[-1, 1]$. The probability that $X^{2}+Y^{2}>1$ is $\pi/4$ $1-\pi/4$ $\pi/2 - 1$ Probability that $X^{2}+Y^{2}<0.5$ None of the above. Probability probability random-variable + – Marv Patel 2.6k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 6 6 votes Area of square denotes the total probability, i. e, 1.Area of circle denotes P(X 2 + Y 2 ≤ 1)Area of shaded region denotes the required probability, i.e, P(X 2+ Y 2 >1)Area of shaded region=Area of square -Area of Circle= 4 - ⊼= 4 ( 1 - ⊼/4)If area of square corresponds to total probability, then4 sq.unit=1= 1 sq.unit=1/4= 4(1-⊼/4) sq.unit==1- ⊼/4 which is the required probability. LeenSharma answered Oct 30, 2015 • selected Dec 25, 2015 by Pooja Palod LeenSharma comment Share Follow 0 reply Please log in or register to add a comment.
2 2 votes (4-Pi)/4....is the answer Marv Patel answered Sep 6, 2014 Marv Patel comment Share Follow See all 2 Comments 2 2 Comments reply Omesh Pandita commented Sep 8, 2014 reply Follow flag 4 - Pi is the area outside circle, you need to divide by total area that is 4 also. 0 0 replyShare Marv Patel commented Sep 8, 2014 reply Follow flag yeahhh man...thanks! 1 1 replyShare Please log in or register to add a comment.