0 0 votes Let the random variable $\text{X}$ has a mixed distributions with probability $\text{P(X = 0)} = \alpha,$ and the density function. $f_{x}(x) = \left\{\begin{matrix} \beta x^{2} (1 – x), 0 < x < 1& \\ 0, \text{otherwise}& \end{matrix}\right.$ If the expectation of $\text{X}$ is $\alpha,$ then the value of $4 \alpha + \beta$ is equal to : $9/2$ $6$ $9$ $5/2$ Probability nielit2021dec-scientistb probability random-variable expectation + – soujanyareddy13 630 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.