0 votes 0 votes Operating System deadlock-prevention-avoidance-detection combinatory counting + – damz1499 asked Nov 7, 2022 damz1499 1.2k views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Kabir5454 commented Nov 7, 2022 reply Follow Share 153 ? 0 votes 0 votes Pranavpurkar commented Nov 7, 2022 reply Follow Share 78? 0 votes 0 votes jugnu1337 commented Nov 7, 2022 reply Follow Share 3+6+a+b <= 22 {condition of deadlock free} a+b<=13 now if a+b = 13 then total 14 possibility a+b=12 13 possibility a+b= 11 12 possibility and so on total possibility 1+2+3+4+5+……..14 = 105 is this approach is correct? 1 votes 1 votes damz1499 commented Nov 8, 2022 i moved by Kabir5454 Nov 8, 2022 reply Follow Share yes ! 153 2 votes 2 votes damz1499 commented Nov 8, 2022 reply Follow Share yes ! 153 0 votes 0 votes jugnu1337 commented Nov 8, 2022 reply Follow Share @damz1499 ok i got it. 0 votes 0 votes Please log in or register to add a comment.