The correct answer to the question "If f(x) = x^2 and g(x) = ln(x), then f(x) + g(x) will be" is "None of the above".
The sum function of f(x) and g(x) is:
f(x) + g(x) = x^2 + ln(x)
This function is neither even nor neither odd. A function is even if it is symmetric with respect to the y-axis, that is, f(-x) = f(x) for all x. A function is odd if it is symmetric with respect to the origin, that is, f(-x) = -f(x) for all x.
We can verify that the sum function is not even as follows:
f(-x) + g(-x) = (-x)^2 + ln(-x) = x^2 + ln(-x)
And f(x) + g(x) = x^2 + ln(x)
Since ln(-x) ≠ ln(x), f(x) + g(x) is not even.
We can also verify that the sum function is not odd as follows:
f(-x) + g(-x) = (-x)^2 + ln(-x) = x^2 + ln(-x)
And -[f(x) + g(x)] = -[x^2 + ln(x)] = -x^2 - ln(x)
Since x^2 + ln(-x) ≠ -x^2 - ln(x), f(x) + g(x) is not odd.
Therefore, the correct answer is "None of the above".