14 votes 14 votes $A$ and $B$ are two events. If $P(A, B)$ decreases while $P(A)$ increases, what must be true: $P(A \mid B)$ decreases $P(B \mid A)$ decreases $P(B)$ decreases All of above Probability goclasses2024_wq8 goclasses probability conditional-probability 1-mark + – GO Classes asked Apr 12, 2023 • edited Apr 12, 2023 by Lakshman Bhaiya GO Classes 1.3k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
4 votes 4 votes P(A,B) = P(A) P(B,A) since P(A,B) decreases with increase in P(A) therefore P(A) is inversely proportional to P(A,B) which implies that P(A,B) is directly proportional to P( B | A ) vinayak_29 answered Apr 13, 2023 vinayak_29 comment Share Follow See all 3 Comments See all 3 3 Comments reply ꧁༒☬ĿọŗԀ 🆂🅷🅸🆅🅰☬༒꧂ commented Apr 13, 2023 reply Follow Share why not A option correct ? According to this statement P(A,B) is directly proportional to P( B | A ) true but P(A|B) is also proportional to P(A, B) so it will also decrease . ?? 3 votes 3 votes Vineeth Rambhiya commented Apr 14, 2023 reply Follow Share Notice that as it was mentioned “P(A,B) decreases while P(A) increases”. Now using equation P(A,B) = P(A) P(B|A) it was able to conclude that P(A) is inversely proportional to P(A,B) and P(B|A) directly proportional to P(A,B) and so P(B|A) decreases In eqaution P(A,B) = P(B) P(A|B), the only known thing is P(A,B) decreases and nothing else. So we cannot tell anything about P(A|B) 4 votes 4 votes anirudhkumar18 commented Apr 16, 2023 reply Follow Share A.P(A/B)=P(A,B)/P(B) ,P(A,B) decreases but we don't know P(B) is decreases or increases so we can’t say anything about P(A/B) decreases or not B.P(B/A)=P(A,B)/P(A) as P(A,B) decreases and P(A) increases so P(B/A) is definitely decreases as P(A) is inversely proportional to P(B/A) 2 votes 2 votes Please log in or register to add a comment.
2 votes 2 votes A and B are the two events .P(A,B)=P(B|A)*P(A) => P(B|A)=P(A,B)/P(A) If P(A,B) decreases and P(A) increases then automatically P(B|A) decreases. SubhamAdhikary answered Apr 17, 2023 SubhamAdhikary comment Share Follow See all 0 reply Please log in or register to add a comment.