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7 votes
7 votes

If $A$ is a $3 \times 3$ matrix such that $A\left(\begin{array}{l}0 \\ 1 \\ 2\end{array}\right)=\left(\begin{array}{l}1 \\ 0 \\ 0\end{array}\right)$ and $A\left(\begin{array}{l}3 \\ 4 \\ 5\end{array}\right)=\left(\begin{array}{l}0 \\ 1 \\ 0\end{array}\right)$, then the product $A\left(\begin{array}{l}6 \\ 7 \\ 8\end{array}\right)$ is ________.

  1. $\left(\begin{array}{l}0 \\ 0 \\ 1\end{array}\right)$
     
  2. $\left(\begin{array}{r}-1 \\ 2 \\ 0\end{array}\right)$
     
  3. $\left(\begin{array}{r}1 \\ -1 \\ 0\end{array}\right)$
     
  4. $\left(\begin{array}{r}9 \\ 10 \\ 11\end{array}\right)$
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1 Answer

20 votes
20 votes

given is of the form $Ax=b$

$Ax_1=b_1$,$Ax_2=b_2$,

$Ax_3=?$

\[
x_3= \begin{pmatrix} 6 \\ 7 \\ 8 \end{pmatrix}=-1\begin{pmatrix} 0 \\ 1 \\ 2 \end{pmatrix} + 2 \begin{pmatrix} 3 \\ 4 \\ 5 \end{pmatrix}
\]

That is question asking $A(-x_1+2x_2)=?$

$A(-x_1+2x_2)=-b_1+2b_2$

\[
-1\begin{pmatrix} 1 \\ 0 \\ 0 \end{pmatrix} + 2 \begin{pmatrix} 0 \\ 1 \\ 0 \end{pmatrix} = \begin{pmatrix} -1 \\ 2 \\ 0 \end{pmatrix}
\]

Answer: