2 votes 2 votes Consider the probability density function \(f(x) = \lambda e^{-\lambda x}\) for \(x \geq 0\) and \(\lambda > 0\). Determine the value of \(\lambda\) such that \(5E(x) = V(x)\). Probability gate2024-da-memory-based goclasses probability expectation numerical-answers + – GO Classes asked Feb 4 • recategorized Feb 4 by Lakshman Bhaiya GO Classes 402 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Exponential Distributionf(x) = $\lambda$e$^{-\lambda x}$Mean in exponential distribution = 1/$\lambda$ = E(X)Variance = 1/$\lambda ^{2}$5/$\lambda$ = 1/$\lambda ^{2}$ $\lambda$ = 1/5 or 0.2 Mrityudoot answered Feb 5 Mrityudoot comment Share Follow See all 0 reply Please log in or register to add a comment.
