3 votes 3 votes Let $\mathcal{P}(A)$ denote the power set of $A$. If $\mathcal{P}(A) \subseteq B$ then $2^{|A|} \leq|B|$ $2^{|A|} \geq|B|$ $2|A|<|B|$ $2^{|A|} \geq 2^{|B|}$ Set Theory & Algebra goclasses2025_cs_wq5 goclasses discrete-mathematics set-theory&algebra set-theory 1-mark + – GO Classes asked Apr 10 • edited Apr 10 by shadymademe GO Classes 126 views answer comment Share Follow See 1 comment See all 1 1 comment reply Deepak Poonia commented Apr 11 reply Follow Share Detailed Video Solution: https://www.youtube.com/watch?v=v5v-AfpwicQ&list=PLIPZ2_p3RNHige8KFyCc4uWDx2uXEq1f0&index=6 1 votes 1 votes Please log in or register to add a comment.
Best answer 2 votes 2 votes $P(A) \subseteq B$ $\left | P(A) \right | \leq \left | B \right |$ $2^{\left | A \right |} \leq \left | B \right |$ Correct Option: A https_guru answered Apr 10 • selected Apr 10 by Deepak Poonia https_guru comment Share Follow See 1 comment See all 1 1 comment reply theabhi100 commented 5 days ago reply Follow Share yes 0 votes 0 votes Please log in or register to add a comment.