A) This is not always true...suppose rank is 5 and dim(Col(A)) = 2 then nul space dimension will be 3.
B) Not true because columns of A are in R11.
C) This is also not true because the solution of Ax = b is of the form:
x = (constant vector) + (combination of LI vectors)
due to constant vector, the solution is not a subspace, it just lies in R5.
D) This is true Ax=0 has infinitely many solutions, then cols of A are LD so rank(A)<5.