0 0 votes what's the condition to draw PDA for a^(2j+1)b^j such that j>=1.Since the language L={aaab,aaaaabb,aaaaaaabbb,.......}. Is pda possible? Theory of Computation pushdown-automata npda dpda + – Vignesh859 368 views answer comment Share Follow Print See 1 comment 1 1 comment reply Shaik Masthan commented May 15, 2024 reply Follow flag yes, PDA possible. where were you struck ? 0 0 replyShare Please log in or register to add a comment.