Recent questions tagged dpda

Which of the Following is/ are correct ?1. Regular Language intersection DCFL = DCFL2. Regular Language Concatination DCFL = CFL3. Regular Language Union ...

Show that $L = \{a^nb^m,n< 2m \}$ is a deterministic context-free language.

what's the condition to draw PDA for a^(2j+1)b^j such that j>=1.Since the language L={aaab,aaaaabb,aaaaaaabbb,.......}.Is pda possible?

I think S1 is false because, for n=0, no 0’s will be added in stack, but in the transition to the next state (q2->q3) there is one mandatory 1 canceling out 0 in stack w...

Identify the type of the given language and draw the corresponding automata for the language.$L=\left \{a^{i}b^{j}c^{k} \space\ | \space\ j=max(i,k) \right \}$A] RegularB...

Construct PDA using empty stack method for the given language.$L=\left \{ x \space\ | \space\ x\in \left \{ a,b \right \}^{*} ; n_{a}(x) >= n_{b}(x) \right \}$//number of...

The proof of Lemma $2.41$ says that $(q, x)$ is a looping situation for a $DPDA \:P$ if when $P$ is started in state $q$ with $x \in \Gamma$ on the top of the stack, it n...

The purpose of this exercise is to show that a one-stack machine with an endmarker on the input has no more power than a deterministic $PDA$. $L\$$ is the concatenation o...

L = { a^m b^n c^k=m+n } Please draw PDA for this Language!

Is this approach of acceptance by empty stack correct ?I am confused because i have read that acceptance by empty stack may not be able to accept all regular languages.

Construct a PDA for the language of all those strings in which the number of $b 's$ is double the number of $a 's$. $a$ and $b$ can occur in any order. For example:$L=\{\...