1 1 vote Hey! is there a shortcut to finding the number of gates to be used in similar questions? I am unable to solve these questions. Please help. Digital Logic digital-logic min-no-gates combinational-circuit + – srishtipandey420 534 views answer comment Share Follow Print See 1 comment 1 1 comment reply Chandrabhan Vishwa 1 commented Jul 11, 2024 reply Follow flag when we put the value in truth tableA B C f(A,B,C )0 0 0 00 0 1 00 1 0 00 1 1 11 0 0 11 0 1 11 1 0 11 1 1 1f(A,B,C)=sigm m (3,4,5,6,7)after minimization this should be equal to A+BCso one OR AND one AND gate required 1 1 replyShare Please log in or register to add a comment.
Best answer 2 2 votes $\underline{\text{Simplification}}:$$A \oplus B \oplus AB = A \oplus (B \oplus AB) = A \oplus B \ (1 \oplus A) = A \oplus B \bar{A} \equiv A + B \bar{A} = A + B $ $A \oplus C \oplus AC = A \oplus (C \oplus AC) = A \oplus C \ (1 \oplus A) = A \oplus C \bar{A} \equiv A + C \bar{A} = A + C $ $\text{So, (A+B)(A+C) = A + BC i.e 1 AND Gate & 1 OR Gate required}$ $\text{Circuit Diagram:}$ CLICK HERE AniMan_7 answered Jul 8, 2024 • selected Jul 15, 2024 by Shaik Masthan AniMan_7 comment Share Follow 0 reply Please log in or register to add a comment.