1 1 vote What is the maximum possible rank of an $\mathrm{m} \times \mathrm{n}$ matrix A that is not square?$\operatorname{rank}(A) \geq \min (m, n)$ $\operatorname{rank}(A) \leq \min (m, n)$ $\operatorname{rank}(A)=\min (m, n)$ $\operatorname{rank}(A)=\max (m, n)$ Linear Algebra goclasses linear-algebra goclasses_questionoftheday rank-of-matrix + – GO Classes 272 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes B, as the max value of rank is min(m,n) for square matrix. So, it will be always less than that. rathi_aryan answered Jun 29, 2025 rathi_aryan comment Share Follow 0 reply Please log in or register to add a comment.
