Let the five consecutive numbers be:
x, x+1, x+2, x+3, x+4x
Their total sum is:
x+(x+1)+(x+2)+(x+3)+(x+4) = 5x+10
Let the number erased be e. Then:
5x+10 − e = 2025
⇒ e = 5x+10−2025
⇒ e = 5x−2015
Now, e must be one of the five numbers:
x, x+1, x+2, x+3, x+4
Let’s check each:
Try e = x:
x = 5x−2015
⇒ 4x = 2015
⇒ x = 503.75 (Not integer)
Try e = x+1:
x+1 = 5x−2015
⇒ 4x = 2016
⇒ x = 504 (Integer)
So, the five numbers are:
504, 505, 506, 507, 508
Total sum: 504+505+506+507+508 =2530
Remove x+1 = 505
Sum of remaining = 2530−505 = 2025
Final Answer:
The erased number is 505.