1 1 vote An organization has subnetted the IP block 200.1.1.0/24 using Variable Length Subnet Masking (VLSM) as follows:Host Requirements:Subnet A: 72 hostsSubnet B: 35 hostsSubnet C: 20 hostsSubnet D: 18 hosts 200.1.1.0/24 | +-------------+-------------+ | | 200.1.1.0/25 200.1.1.128/25 [Subnet A] | +----------+-----------+ | | 200.1.1.128/26 200.1.1.192/26 [Subnet B] | +--------+--------+ | | 200.1.1.192/27 200.1.1.224/27 [Subnet C] [Subnet D] The organization now needs to add a fifth subnet (Subnet E) requiring 20 new hosts. Which of the following is the most appropriate way to accommodate Subnet E without requesting a new network block?Convert Subnet D from /27 to /28 and use the leftover space for Subnet EMerge Subnets B and C to free up a /25 block for Subnet ESplit Subnet A (200.1.1.0/25) into four /27 subnets, assign three to Subnet A and one to Subnet EUse the unused space after Subnet D (200.1.1.255/32) to create Subnet E Computer Networks computer-networks + – Sachin Mittal 1 280 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote Answer: CThe original IP block 200.1.1.0/24 contains 256 addresses. The organization has already created four subnets using VLSM:200.1.1.0/25 — Subnet A (supports up to 126 hosts)200.1.1.128/26 — Subnet B (supports up to 62 hosts)200.1.1.192/27 — Subnet C (supports up to 30 hosts)200.1.1.224/27 — Subnet D (supports up to 30 hosts)Now, we need to accommodate Subnet E requiring 20 hosts. A /27 subnet offers 32 IP addresses (30 usable), which is ideal for Subnet E.Looking at the current allocation:Subnet D ends at 200.1.1.255, so the entire 200.1.1.0/24 block is already allocated — there is no space "after" Subnet D.Merging Subnets B and C would waste space and disturb existing configuration.Changing Subnet D from /27 to /28 would only save 16 IPs — not enough for a new subnet needing 20 hosts.However, Subnet A has been allocated a /25, which supports 126 hosts but only needs 72. It can be split into smaller subnets.We can divide 200.1.1.0/25 into four subnets of size /27 (each supporting up to 30 hosts):200.1.1.0/27200.1.1.32/27200.1.1.64/27200.1.1.96/27Three of them can be assigned to Subnet A (totaling 90 usable hosts), and one can be used for Subnet E (30 usable hosts).Hence, the correct approach is to split Subnet A into four /27 subnets, reassign three to Subnet A and use one for Subnet E. Sachin Mittal 1 answered Jul 9, 2025 Sachin Mittal 1 comment Share Follow 0 reply Please log in or register to add a comment.