0 0 votes The $\text{LU}$ factorization requires:$\dfrac{n^{3}}{6}-\dfrac{n}{5}$ multiplication/division$\dfrac{n^{3}}{3}-\dfrac{n^{2}}{2}+\dfrac{n}{6}$ addition/subtraction$\dfrac{n^{3}}{5}-\dfrac{n^{2}}{3}+\dfrac{n}{6}$ addition/subtractionNone of the above Algorithms nielit-sta-2025 linear-algebra numerical-methods + – Shubham Sharma 2 115 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.