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A box of a certain brand of washing powder advertises that it weighs $2.5$ kg, but the actual weight is $2.4$ kg with a standard deviation of $0.1$ kg. The company wants to test if the mean has changed. They take a random sample of $100$ boxes and find that the average weight is $2.35$ kg.

What conclusion should be made using a significance level of $\alpha=0.05$?

Note: Let $Z$ be a standard normal random variable. You may use the following information:

  • $P(Z>1.96)=0.025$
     
  • $P(Z<-1.96)=0.025$

 

  1. Reject $H_0$.
     
  2. Fail to reject $H_0$.
     
  3. Accept $H_0$.
     
  4. Accept $H_A$.

1 Answer

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The company wants to check if the mean has changed. So, null and alternative hypothesis are given by

$$
H_0: \mu=2.4, \quad \mu \neq 2.4
$$

Define a test statistic $T$ as $T=\bar{X}$.

Test: reject the null hypothesis if $|\bar{X}-2.4|>c$.

By CLT, we can say that $\frac{\bar{X}-2.4}{0.1 / \sqrt{100}}=\frac{\bar{X}-2.4}{1 / 100} \sim \operatorname{Normal}(0,1)$.

Now,

$$
\begin{aligned}
\alpha & =P(|\bar{X}-2.4|>c) \\
\Longrightarrow 0.05 & =P\left(\left|\frac{\bar{X}-2.4}{1 / 100}\right|>\frac{c}{1 / 100}\right) \\
\Longrightarrow 0.05 & =P(|Z|>100 c) \\
\Longrightarrow 0.05 / 2 & =P(Z<-100 c) \\
\Longrightarrow-1.96 & =-100 c \Longrightarrow c=0.0196
\end{aligned}
$$

Since $|\bar{X}-2.4|=|2.35-2.4|=0.05>c$, reject $H_0$.
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