Aptitude

Question

An article was sold at a discount of 15% and there was a profit of 20%. If the gained was 6 rupees  less than the discount offered, what was the selling price of the article ?

Comments

ANS=134.4

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@asu Can u provide your sol ?

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Let Selling Price = S

 Marketing Price = M

Purchased Price = P

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Given, Discount  = 15%.

So,               S   = 0.85 M         ---------(1)

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Given, Profit = 20 %

So,               S   = 1.2 P         ----------(2)

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The gained was 6 rupees less than the discount offered,

So,             0.2P(gain)  = 0.15M(discount) - 6            ------(3)

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From eqn (2) and (3), trying to eliminate P,

              S = (1.2 / 0.2) * (0.15M - 6)     

using equation (1),

 =>        S = 6 ( (15/85) S - 6 )

 =>        S = (90/85) S - 36

 =>        S(90/85 - 1)   = 36

 =>        S  = (36*85)/5 = 36*17 =  612

Answer 1

Let $\text{SP} =x$

$\text{CP}= \text{SP} \times \frac{100}{120} = \frac{5x}{6}$

$\text{MP} = \text{SP} \times \frac{100}{85} = \frac{20x}{17}$

$\text{Profit}=\frac{x}{6}$

$\text{Discount}=\frac{3x}{17}$

$\frac{3x}{17} - \frac{x}{6}=6$

$\implies x=612.$

Answer 2

...............................

Comments

Wrong approach

Last equation terribly wrong. It satisfies discount of 15 % but does not satisfies profit of 20%. Instead it satisfies that selling price is 94 greater than discount

Answer 3

SP = 0.85. MP

SP = 1.2 CP

0.2 CP = 0.15 MP - 6

3 equations and 3 variables. We need to get SP. So,

SP = 0.85 (0.2CP + 6)/0.15
= 3.4/3 CP + 34

= 3.4/3 SP /1.2 + 34
= 17/18 SP + 34

SP = 34 * 18 = 680 - 68 = 612

Answer 4

Let the MRP be Rs.x

discount=15x/100

SP=MRP-Discount=x-15x/100=85x/100

Gain=20%of SP=17x/100

As CP=SP-Gain=85x/100-17x/100=68x/100

Given that Gain =Rs.6

Gain=SP-CP=85x/100-68x/100=17x/100=Rs.6

x=rs.35.29412

SP=85x/100=Rs.30

CP=68x/100=Rs.24

Answer 5

134.4