0 votes 0 votes consider the relation r1(P,Q,R) and r2(R,S,T) with primary key P and R respectively. r1 contain 2000 tuples and r2 2500 tuples. max size of natural joint of r1 and r2..? plz explain.. dhairya asked Jun 16, 2016 dhairya 1.4k views answer comment Share Follow See 1 comment See all 1 1 comment reply rude commented Jun 16, 2016 i edited by rude Jun 16, 2016 reply Follow Share The max size will be Min $(2000, 2500) = 2000$ tuples. Here is the reference. 1 votes 1 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes See here R is common in both the relation .Also R is key in the second relation .In second relation R will have 2500 distinct value. Also Relation r1 has 2000 tuple .So here every tuple in relation r1 will map with the relation r2 .So it will give result 2000 tuple. So Maximum size of R1⋈ R2 =2000 Also Minimum tuple in R1⋈ R2 =2000 ManojK answered Jun 16, 2016 • reshown Jun 16, 2016 by ManojK ManojK comment Share Follow See all 25 Comments See all 25 25 Comments reply Show 22 previous comments ManojK commented Jun 16, 2016 reply Follow Share I should provide one line for answering this question.Then only it will be clear .Instead of up voting you down voting the answer.Ok No problem.If you have still any doubt you can ask. 0 votes 0 votes dhairya commented Jun 17, 2016 reply Follow Share thanxxxx manojk i got it now....:) 1 votes 1 votes ManojK commented Jun 17, 2016 reply Follow Share thank you . 0 votes 0 votes Please log in or register to add a comment.