6 6 votes A Boolean function $F(A, B, C, D)=\sum m(0,1,2,5,8,9,10)$ is given. Which of the following represents the most simplified Sum of Products (SOP) form?$\bar{B} \bar{D}+\bar{B} \bar{C}+\bar{A} C \bar{D}$ $\bar{B} \bar{D}+\bar{A} \bar{B}+\bar{A} \bar{C} D$ $\bar{B} \bar{C}+\bar{B} \bar{D}+\bar{A} \bar{C} D$ $\bar{B} \bar{D}+\bar{B} \bar{C}+\bar{A} \bar{C} \bar{D}$ Digital Logic goclasses digital-logic goclasses-cs-dpp goclasses-cs-dpp-day-201 goclasses-digital-logic-practice-questions + – GO Classes 252 views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply Sameer_Kumar 2 commented Feb 20 reply Follow flag C 0 0 replyShare Prashant-G commented Jun 10 reply Follow flag Correct answer is option -C ✅ 0 0 replyShare Please log in or register to add a comment.
1 1 vote \begin{aligned} &\begin{array}{lllll} & C D(00) & C D(01) & C D(11) & C D(10) \\ A B(00) & 1(\mathrm{m} 0) & 1(\mathrm{m} 1) & 0 & 1(\mathrm{m} 2) \\ A B(01) & 0 & 1(\mathrm{~m} 5) & 0 & 0 \\ A B(11) & 0 & 0 & 0 & 0 \\ A B(10) & 1(\mathrm{m} 8) & 1(\mathrm{m} 9) & 0 & 1(\mathrm{m} 10) \end{array}\\\\ &F=\bar{B} \bar{D}+\bar{B} \bar{C}+\bar{A} \bar{C} D \end{aligned} GO Classes answered Feb 20 GO Classes comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Here is the Explanation Prashant-G answered Jun 10 Prashant-G comment Share Follow 0 reply Please log in or register to add a comment.