$$
A\left(\begin{array}{c}
1 \\
1 \\
\ldots \\
1
\end{array}\right)
$$
gives a column vector each of whose entries is the row sum, $r$ say.
Then
$$
\begin{gathered}
2 A\left(\begin{array}{c}
1 \\
1 \\
\ldots \\
1
\end{array}\right)=2\left(\begin{array}{c}
r \\
r \\
\ldots \\
r
\end{array}\right)=\left(\begin{array}{c}
2 r \\
2 r \\
\ldots \\
2 r
\end{array}\right) . \\\\
A^2\left(\begin{array}{c}
1 \\
1 \\
\ldots \\
1
\end{array}\right)=A\left(\begin{array}{c}
r \\
r \\
\ldots \\
r
\end{array}\right)=r A\left(\begin{array}{c}
1 \\
1 \\
\ldots \\
1
\end{array}\right)=\left(\begin{array}{c}
r^2 \\
r^2 \\
\ldots \\
r^2
\end{array}\right) \\\\
A^{-1}\left(\begin{array}{c}
r \\
r \\
\ldots \\
r
\end{array}\right)=A^{-1} A\left(\begin{array}{c}
1 \\
1 \\
\ldots \\
1
\end{array}\right)=\left(\begin{array}{c}
1 \\
1 \\
\ldots \\
1
\end{array}\right)
\end{gathered}
$$
and therefore
$$
A^{-1}\left(\begin{array}{c}
1 \\
1 \\
\ldots \\
1
\end{array}\right)=\left(\begin{array}{c}
r^{-1} \\
r^{-1} \\
\ldots \\
r^{-1}
\end{array}\right)
$$