1 1 vote Consider the family of functions$$g(x)=a \ln (x)+\frac{b}{x}$$defined for $x>0,$ where $a$ and $b$ are positive constants.Any function $g(x)$ in this family has only one critical point. In terms of $a$ and $b,$ what is the $x$-coordinate of that critical point?$x=b / a$ is a critical point where the function shows local maxima$x=a / b$ is a critical point where the function shows local minima$x=b / a$ is a critical point where the function shows local minima$x=a / b$ is a critical point where the function shows local maxima Calculus goclasses2026-iiith-mock-12 goclasses one-mark calculus engineering-mathematics + – GO Classes 341 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes Detailed Video Solution: https://youtu.be/6aIuj2b2J38 Since$$g^{\prime}(x)=\frac{a}{x}-\frac{b}{x^2}=\frac{a x-b}{x^2}$$we see that $g^{\prime}(x)=0$ when $a x-b=0$, i.e. when $x=\dfrac{b}{a}$.We use the $2^{\text{nd}}$ derivative test. Since$$g^{\prime \prime}(x)=-\frac{a}{x^2}+\frac{2 b}{x^3}=\frac{-a x+2 b}{x^3}$$we have that$$g^{\prime \prime}\left(\frac{b}{a}\right)=\frac{-a \frac{b}{a}+2 b}{\left(\frac{b}{a}\right)^3}=\frac{(-b+2 b) a^3}{b^3}=\frac{a^3}{b^2}>0 . \quad {\color{Red}{\text {(local minima)}}}$$ GO Classes answered Apr 13 GO Classes comment Share Follow 0 reply Please log in or register to add a comment.