4 4 votes For the Boolean function $\mathrm{F}(\mathrm{A},\mathrm{B},\mathrm{C},\mathrm{D})=\Pi _M(3,6,7,12,14)$, which of the following is a correct minimal POS form using K-map?$\mathrm{F}=(\mathrm{A}+\mathrm{C}+\mathrm{D}')(\mathrm{A}'+\mathrm{B}'+\mathrm{D})(\mathrm{B}'+\mathrm{C}'+\mathrm{D})$ $\mathrm{F}=(\mathrm{A}+\mathrm{C}'+\mathrm{D}')(\mathrm{A}'+\mathrm{B}'+\mathrm{D}')(\mathrm{B}'+\mathrm{C}'+\mathrm{D})$ $\mathrm{F}=(\mathrm{A}+\mathrm{C}'+\mathrm{D}')(\mathrm{A}'+\mathrm{B}'+\mathrm{D})(\mathrm{B}'+\mathrm{C}'+\mathrm{D})$ $\mathrm{F}=(\mathrm{A}+\mathrm{C}'+\mathrm{D}')(\mathrm{A}'+\mathrm{B}+\mathrm{D})(\mathrm{B}'+\mathrm{C}'+\mathrm{D})$ Digital Logic goclasses goclasses-cs-dpp digital-logic goclasses-cs-dpp-day-296 goclasses-digital-logic-practice-questions k-map + – GO Classes 272 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes Given $\mathrm{F}(\mathrm{A},\mathrm{B},\mathrm{C},\mathrm{D})=\Pi _M(3,6,7,12,14)$.Since maxterms are given, these are the cells where $\mathrm{F}=0$.So, place $0$s at $\mathrm{m}_3,\mathrm{m}6,\mathrm{m}7,\mathrm{m}{12},\mathrm{m}{14}$. Answer: C GO Classes answered Jun 12 GO Classes comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes if this questionis MSQ then one more answer along with option C is : (A'+ B '+ D)(A+ C' + D') (A + B' + C') . akash_kumar 9 answered Jun 12 akash_kumar 9 comment Share Follow See 1 comment 1 1 comment reply GO Classes commented Jun 13 reply Follow flag Nice Catch @akash_kumar 9! That could have been one more solution, we have added one MSQ question also so that this concept doesnt catch you offguard during the exam!! 3 3 replyShare Please log in or register to add a comment.
0 0 votes Option C pratishamacha answered Jun 14 pratishamacha comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Here is the Explanation 👇 correct answer is option C ✅ Prashant-G answered Jun 15 Prashant-G comment Share Follow 0 reply Please log in or register to add a comment.