1 1 vote Consider the following Python code:def first(): print("A") def second(): print("B") first() print("C") print("Start") second() print("End")What is the output of the code above?Start A B C EndStart B A C EndB A C Start EndStart B C A End Programming in Python goclasses goclasses-da-dpp goclasses-da-dpp-day-204 programming-in-python goclasses-python-&-dsa-practice-questions output functions + – GO Classes 94 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes Function bodies do not execute when the function is defined. They execute only when the function is called.First, Python executes:print("Start")So the first output is $\texttt{Start}$.Then $\texttt{second()}$ is called. Inside $\texttt{second()}$, Python first prints $\texttt{B}$.Then $\texttt{first()}$ is called, so Python enters $\texttt{first()}$ and prints $\texttt{A}$.After $\texttt{first()}$ finishes, control returns to $\texttt{second()}$, and $\texttt{C}$ is printed.Finally, after $\texttt{second()}$ finishes, Python prints $\texttt{End}$.Therefore, the output is:Start B A C EndCorrect Option: B GO Classes answered Jun 19 GO Classes comment Share Follow 0 reply Please log in or register to add a comment.