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GO Classes DPP | GATE DA | Python Programming | Return In Loop

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The function searches for $\texttt{target = 6}$ inside the list.

The loop starts with $\texttt{x = 2}$. It prints $\texttt{2}$, but $\texttt{2 == 6}$ is false.

Next, $\texttt{x = 4}$. It prints $\texttt{4}$, but $\texttt{4 == 6}$ is false.

Next, $\texttt{x = 6}$. It prints $\texttt{6}$, and now $\texttt{x == target}$ is true.

So the function immediately returns:

x + 10 = 6 + 10 = 16

Once a return statement executes, the function stops. So $\texttt{8}$ is not printed.

The returned value $\texttt{16}$ is printed by the outer $\texttt{print()}$.

Therefore, the output is:

2
4
6
16


Correct Option: A

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