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A $3$-bit binary up counter counts in normal binary order.

Starting state:

$000$

After $1^\text{st}$ clock pulse:

$001$

After $2^\text{nd}$ clock pulse:

$010$

After $3^\text{rd}$ clock pulse:

$011$

After $4^\text{th}$ clock pulse:

$100$

After $5^\text{th}$ clock pulse:

$101$

So, after $5$ clock pulses, the counter state is $101$.


Answer: C

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