Question

What is the highest address in 48 K memory? (in decimal)

a. 49151

b. 49152

c. 64386

d. 64387

Answer 1

A) In a 48K memory Number of bits required is =log(48 * 1024)=16 bit

Now this 16 bit can represent highest address as (2^16)-1 =65535

             But since the memory is only 48K it will represent highest address as (48*1024)-1=49151 (since one of the address will be 0)

Answer 2

A ) 49151

considering n bits address.

since the addressing starts from 0 to (2^n)-1.