Time required to read 800 successive sectors ?

Question

A certain hard disk rotates at 6000 rpm. It has 1KB per sector and 64 sectors per track and has a seek time of 5ms. The time required to read 800 successive sectors is?

800 successive sectors means 12 complete tracks and 32 sectors of the 13th track.
(this is not random 800 sectors that we can just multiply by 800 , with tseek+trot+ttrans).

Answer 1

Avg rotational latency = 5ms

 

Answer

= avg. seek time + time to get to starting sector(or avg rotational latency ) + rotational latency for req. no of sectors

= 5ms + 5ms + [  (12 tracks * 10ms rotational latency) + (time to read 32 sectors  of 13th track)  ]

= 10 + 120 + 5

= 135ms

Comments

I got the same, except for the last part.
I did the reading of 32 sectors like this :

to read 64 sectors , you need 10ms

to read 32 sectors, you need 5ms

hence i got : 10+120+5 =135 ms

why are you multiplying 32 with 5?

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ohhh.....You are right. correcting the answer.

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What about the seek time to move head while reading the next 12 consecutive tracks? Should not that be taken into account?
12*5=60ms
135+60=195ms ?????