1 1 vote Digital Logic digital-logic + – _Dipak_ 922 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 1 1 vote Initially Q1Q0 =00 so D1D0 = 01 [as in fig. D1 = Q0 and D0= $\bar{Q1}$] then on each clock pulse [As Qt+1 = D , D1 passes to Q1 and D0 Passes to Q0] so Q1Q0=01 so D1D0 = 11 then Q1Q0=11 so D1D0 = 10then Q1Q0=10 so D1D0 = 00then Q1Q0=00 and same. Praveen Saini answered Apr 17, 2015 • selected Apr 17, 2015 by _Dipak_ Praveen Saini comment Share Follow 0 reply Please log in or register to add a comment.
2 2 votes ans B gate2016 answered Apr 17, 2015 gate2016 comment Share Follow See 1 comment 1 1 comment reply Kaluti commented Oct 4, 2017 reply Follow flag answer coming out to be b as q1+ = q0 q0+ = q1' 0 0 replyShare Please log in or register to add a comment.