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Recent questions tagged min-sum-of-products-form
2
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1
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1
GO Classes 2023 | IIITH Mock Test 1 | Question: 39
Consider a $4$ input boolean function $\mathrm{F}(\mathrm{X}, \mathrm{Y}, \mathrm{Z}, \mathrm{T})$. The minterm $\mathrm{X}^{\prime} \mathrm{Y}^{\prime} \mathrm{Z}^{\prime} \mathrm{T}^{\prime}$ is known to be in the SOP form ... implicant of $F$ is a Prime Implicant. $\mathrm{F}=\mathrm{X} \oplus \mathrm{Y} \oplus \mathrm{Z} \oplus \mathrm{T}$
GO Classes
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in
Digital Logic
Mar 26, 2023
by
GO Classes
720
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goclasses2023-iiith-mock-1
goclasses
digital-logic
boolean-algebra
min-sum-of-products-form
prime-implicants
multiple-selects
1-mark
24
votes
3
answers
2
GATE CSE 2021 Set 2 | Question: 52
Consider a Boolean function $f(w,x,y,z)$ such that $\begin{array}{lll} f(w,0,0,z) & = & 1 \\ f(1,x,1,z) & =& x+z \\ f(w,1,y,z) & = & wz +y \end{array}$The number of literals in the minimal sum-of-products expression of $f$ is _________
Arjun
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in
Digital Logic
Feb 18, 2021
by
Arjun
13.1k
views
gatecse-2021-set2
digital-logic
boolean-algebra
min-sum-of-products-form
numerical-answers
2-marks
0
votes
1
answer
3
Morris Mano Edition 3 Exercise 2 Question 15 (Page No. 71)
The sum of all the minterms of the boolean function of the n variable is 1. Prove the above statement with n = 3. give a Procedure for a general proof
ajaysoni1924
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in
Digital Logic
Mar 31, 2019
by
ajaysoni1924
3.7k
views
digital-logic
morris-mano
boolean-algebra
min-sum-of-products-form
1
vote
2
answers
4
Morris Mano Edition 3 Exercise 2 Question 13 (Page No. 71)
Express the complement of the following function in the sum of minterms. $(a) F(A,B,C,D) = \sum(0,2,6,11,13,14)$ $(b) F(x,y,z) = \prod(0,3,6,7)$
ajaysoni1924
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in
Digital Logic
Mar 31, 2019
by
ajaysoni1924
3.1k
views
digital-logic
morris-mano
boolean-algebra
min-sum-of-products-form
0
votes
0
answers
5
Digital Logic - Min Sum Of Products Form
What is the minimum SOP expression for the following f(a,b,c,d) = Σm(8, 10, 11, 12, 13, 15) + Σd(7, 9 , 14)? I’m getting only “a” as the answer, but the answer given is “a + bcd”. My doubt – the “Dont care term” generating the expression “bcd” is NOT necessary, and it is NOT considered as an Essential Prime Implicant. Please correct if I’m wrong
Hopealways
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in
Digital Logic
Dec 31, 2018
by
Hopealways
462
views
digital-logic
min-sum-of-products-form
0
votes
0
answers
6
Minimization of POS
Please verify my approach for calculation the minimal POS form for a function f. STEPS: Find out the f' in sum of minterms. Minimize f' and find out minimal SOP form. Using DeMorgan's law, find out f. The calcuated f will be minimal and in ... approach. However, I need a confirmation whether this method is actually correct and is bound to give me correct results all the time..!
Harsh Kumar
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in
Digital Logic
Jul 26, 2018
by
Harsh Kumar
511
views
digital-logic
k-map
min-sum-of-products-form
29
votes
3
answers
7
GATE CSE 2018 | Question: 49
Consider the minterm list form of a Boolean function $F$ given below. $F(P, Q, R, S) = \Sigma m(0, 2, 5, 7, 9, 11) + d(3, 8, 10, 12, 14)$ Here, $m$ denotes a minterm and $d$ denotes a don't care term. The number of essential prime implicants of the function $F$ is ___
gatecse
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Digital Logic
Feb 14, 2018
by
gatecse
16.2k
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gatecse-2018
digital-logic
min-sum-of-products-form
numerical-answers
2-marks
2
votes
1
answer
8
MadeEasy Test Series 2018: Digital Logic - Min Sum Of Products Form
A switching function of four variable, is equal to the product of two other functions f1and f2, of the same variable, i.e. f = f1 f2. The function f and f1 are as follows: The number of full specified function, that will satisfy the given condition, is
mohit kumar 5
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Digital Logic
Jan 12, 2018
by
mohit kumar 5
972
views
digital-logic
min-sum-of-products-form
made-easy-test-series
madeeasy-testseries-2018
0
votes
1
answer
9
Digital Systems - Min/Max-Term Expressions
From the following tables Two bits equality detector: x1 x2 y1 y2 f 0 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 0 1 1 0 0 1 0 0 0 0 1 0 1 1 0 1 1 0 0 0 1 1 1 0 1 0 0 0 0 1 0 0 1 0 1 0 1 0 1 1 0 1 1 0 1 1 0 0 0 1 ... of the f output of two bits equlity detector. Write down the max-term expression of the f output of the truth table below: x y f 0 0 0 0 1 1 1 0 0 1 1 1
Garrett McClure
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in
Digital Logic
Sep 7, 2017
by
Garrett McClure
666
views
digital-logic
min-sum-of-products-form
digital-circuits
1
vote
1
answer
10
Test by Bikram | Mock GATE | Test 4 | Question: 36
Which of the following statements is/are CORRECT? $S_1$: Max term is a sum term which contains all the variables in either direct or complementary form. $S_2$: Min term is a product term which contains all the variables in either direct or ... $S_3$ is correct only $S_2$ is correct All $S_1$, $S_2$ and $S_3$ are correct
Bikram
asked
in
Digital Logic
May 14, 2017
by
Bikram
421
views
tbb-mockgate-4
digital-logic
simplification
min-sum-of-products-form
0
votes
1
answer
11
MadeEasy Subject Test: Digital Logic - Min Sum Of Products Form
vaishali jhalani
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in
Digital Logic
Jan 30, 2017
by
vaishali jhalani
628
views
made-easy-test-series
digital-logic
min-sum-of-products-form
5
votes
1
answer
12
Number of Boolean function possible
Number of boolean function with 3 boolean variable such that the function contain exactly 2 or 7 min term in their canonical SOP? Please explain the logic!
smartmeet
asked
in
Digital Logic
Jan 8, 2017
by
smartmeet
3.5k
views
combinatory
min-sum-of-products-form
17
votes
1
answer
13
GATE CSE 1988 | Question: 2-v
Three switching functions $f_1, \: f_2 \:$ and $f_3$ are expressed below as sum of minterms. $f_1 (w, x, y, z) = \sum \: 0, 1, 2, 3, 5, 12$ $f_2 (w, x, y, z) = \sum \: 0, 1, 2, 10, 13, 14, 15$ $f_3 (w, x, y, z) = \sum \: 2, 4, 5, 8$ Express the function $f$ realised by the circuit shown in the below figure as the sum of minterms (in decimal notation).
go_editor
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in
Digital Logic
Dec 11, 2016
by
go_editor
2.5k
views
gate1988
descriptive
digital-logic
easy
circuit-output
min-sum-of-products-form
0
votes
1
answer
14
GATE Overflow | Digital Logic | Test 1 | Question: 2
Find the minimum sum of products form of the below Logic function : $F(A,B,C,D) = \sum m(0,2,8,10,15) + \sum d(3,11,12,14)$ where $m$ and $d$ are min-terms and don’t care conditions respectively. $AC +\bar BC \bar D +B\bar C $ $\bar B \bar D + AC$ $\bar AC +BC+\bar B\bar C \bar D$ $B\bar C\bar D + \bar BA + CA$
Bikram
asked
in
Digital Logic
Sep 19, 2016
by
Bikram
246
views
digital-logic
go-digital-logic-1
min-sum-of-products-form
20
votes
2
answers
15
GATE CSE 1991 | Question: 5-b
Find the minimum sum of products form of the logic function $ f(A,B,C,D) = \Sigma_{m}(0,2,8,10,15)+ \Sigma _{d}(3,11,12,14)$ where $m$ and $d$ represent minterm and don't care term respectively.
ibia
asked
in
Digital Logic
Nov 14, 2015
by
ibia
3.2k
views
gate1991
digital-logic
boolean-algebra
min-sum-of-products-form
descriptive
21
votes
1
answer
16
GATE CSE 1997 | Question: 71
Let $f=(\bar{w} + y)(\bar{x} +y)(w+\bar{x}+z)(\bar{w}+z)(\bar{x}+z)$ Express $f$ as the minimal sum of products. Write only the answer. If the output line is stuck at $0$, for how many input combinations will the value of $f$ be correct?
go_editor
asked
in
Digital Logic
Oct 15, 2015
by
go_editor
3.1k
views
gate1997
digital-logic
min-sum-of-products-form
numerical-answers
20
votes
2
answers
17
GATE IT 2008 | Question: 8
Consider the following Boolean function of four variables $f(A, B, C, D) = Σ(2, 3, 6, 7, 8, 9, 10, 11, 12, 13)$ The function is independent of one variable independent of two variables independent of three variable dependent on all the variables
Ishrat Jahan
asked
in
Digital Logic
Oct 28, 2014
by
Ishrat Jahan
6.2k
views
gateit-2008
digital-logic
normal
min-sum-of-products-form
24
votes
7
answers
18
GATE CSE 2011 | Question: 14
The simplified SOP (Sum of Product) from the Boolean expression $(P + \bar{Q} + \bar{R}) . (P + \bar{Q} + R) . (P + Q +\bar{R})$ is $(\bar{P}.Q+\bar{R})$ $(P+\bar{Q}.\bar{R})$ $(\bar{P}.Q+R)$ $(P.Q+R)$
go_editor
asked
in
Digital Logic
Sep 29, 2014
by
go_editor
9.5k
views
gatecse-2011
digital-logic
normal
min-sum-of-products-form
18
votes
1
answer
19
GATE CSE 2014 Set 3 | Question: 7
Consider the following minterm expression for $F$: $F(P,Q,R,S) = \sum 0,2,5,7,8,10,13,15$ The minterms $2$, $7$, $8$ and $13$ are 'do not care' terms. The minimal sum-of-products form for $F$ is $Q \bar S+ \bar QS$ $ \bar Q \bar S+QS$ $ \bar Q \bar R \bar S+ \bar QR \bar S+Q \bar R S+QRS$ $ \bar P \bar Q \bar S+ \bar P QS+PQS+P \bar Q \bar S$
go_editor
asked
in
Digital Logic
Sep 28, 2014
by
go_editor
4.6k
views
gatecse-2014-set3
digital-logic
min-sum-of-products-form
normal
37
votes
4
answers
20
GATE CSE 2014 Set 1 | Question: 45
Consider the $4\text{-to-1}$ multiplexer with two select lines $ S_1$ and $ S_0 $ given below The minimal sum-of-products form of the Boolean expression for the output $F$ of the multiplexer is $\bar{P}Q + Q\bar{R} + P\bar{Q}R$ $\bar{P}Q + \bar{P}Q\bar{R} + PQ\bar{R} + P\bar{Q}R$ $\bar{P}QR + \bar{P}Q\bar{R} + Q\bar{R} + P\bar{Q}R$ $PQ\bar{R}$
go_editor
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in
Digital Logic
Sep 28, 2014
by
go_editor
13.0k
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gatecse-2014-set1
digital-logic
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multiplexer
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