The negation of the above statement is strings containing <=2 consecutive 0's and <=2 consecutive 1's
Let,
T(n) = strings starting with 0 or 00
X(n) = strings starting with 1 or 11
Thus,
T(n) = starts with 0 * X(n-1) + starts with 00 * X(n-2)
X(n) = starts with 1 * T(n-1) + starts with 11 * T(n-2)
Adding both will give the strings containing <=2 consecutive 0's and <=2 consecutive 1's.
Thus, to get answer, substract the abov number.