0 votes 0 votes $\lim_{x\rightarrow \infty }\frac{\sin x}{x}$ Calculus calculus limits + – saket nandan asked Jul 10, 2015 • retagged Aug 2, 2015 by Arjun saket nandan 469 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 3 votes 3 votes $\sin x$ value is bounded from -1 to 1. So as x tends to $\infty$, $\frac{\sin x}{x}$ must be 0. Arjun answered Jul 11, 2015 • selected Jul 12, 2015 by saket nandan Arjun comment Share Follow See 1 comment See all 1 1 comment reply saket nandan commented Jul 12, 2015 reply Follow Share yes for all real value of x range of sinx will be [-1 to 1] and this value is divided by infinity its value will be 0 1 votes 1 votes Please log in or register to add a comment.
1 votes 1 votes remember this as a standard formula .as it always give answer as 0 focus _GATE answered Jul 11, 2015 focus _GATE comment Share Follow See all 2 Comments See all 2 2 Comments reply saket nandan commented Jul 11, 2015 reply Follow Share HOW? 0 votes 0 votes Arjun commented Jul 11, 2015 reply Follow Share $\sin x$ value is bounded and periodic so as x tends to $\infty$ $\frac{\sin x}{x}$ must be 0. 0 votes 0 votes Please log in or register to add a comment.