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block nested query

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Consider a relation R with 2000 records and relation S with 500 records. Size of each record is 5 Byte and block size is 100 Byte, then minimum number of block access that are needed block nested loop join. I think its answer should be 2525.
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If we have ∀x(p(x)) then in boolean algebra form we can write this statement as (P1 + P2) where + signifies OR which makes it very easy to deal with. So likewise is there any way to have a view of a statement like ∀x∀y(R(x,y)) into boolean form?
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