1 votes 1 votes Hi , Can someone please explain the disjunctive normal form? At few websites, I found it is a disjunction of conjunction of literals. If that is the case, then A^B is not DNF . Also not(A+B) is not DNF. Please answer Digital Logic dnf + – abhijit asked Nov 12, 2017 abhijit 509 views answer comment Share Follow See 1 comment See all 1 1 comment reply Rupendra Choudhary commented Nov 12, 2017 reply Follow Share Disjunctive normal form :- it's SOP form to represent logical formula. SOP = sum of product like if f(A,B,C) then AB'+BC+B'C is sum of three product terms. There is another term name canonical DNF , in which in product term every variable must appear like AB+BC is SOP and AB(C+C')+BC(A+A')=ABC+ABC'+A'BC is Canonical DNF. about your case A.B is not DNF , right , it's not following basic representation of SOP. 0 votes 0 votes Please log in or register to add a comment.